A) \[0,\,\,21.98\,\,J{{K}^{-1}}\,mol{{e}^{-1}}\]
B) -ve, zero
C) \[+ve,\,\,21.98\,\,J{{K}^{-1}}\,mol{{e}^{-1}}\]
D) Zero, zero
Correct Answer: A
Solution :
Since the given process is in equilibrium, i.e., \[\Delta G=0\] \[\Delta G=\Delta H-T\,\Delta S\] or, \[0=\Delta H-T\Delta \,S\text{ }or\text{ }\Delta H=T\Delta S\] or, \[\Delta S=\frac{\Delta H}{T} = \frac{6}{273}\,\,\times \, 1{{0}^{3}} J{{K}^{-1}} mol{{e}^{-1}}\] \[-\,21.98 J{{K}^{-1}}\,mol{{e}^{-}}^{1}\]
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