NEET Sample Paper NEET Sample Test Paper-71

  • question_answer
    Calculate the maximum efficiency of an engine operating between \[110{}^\circ C and 25{}^\circ C\]

    A) \[11.1%\]                      

    B) \[22.2%\]

    C) \[33.3\,%\]                    

    D) \[44.4\,%\]

    Correct Answer: B

    Solution :

    Maximum efficiency of an engine working between temperatures \[{{T}_{2}}\,\,and\,\,{{T}_{1}}\] is given by \[\eta =\frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{2}}}=\frac{383-293}{383}=\frac{85}{383}=0.222\] \[\eta \,\,=\,\,22.2\,%\]


You need to login to perform this action.
You will be redirected in 3 sec spinner