A) \[6.023 \times 1{{0}^{20}}\]
B) \[6.023 \times 1{{0}^{21}}\]
C) \[6.023 \times 1{{0}^{22}}\]
D) \[6.023 \times 1{{0}^{23}}\]
Correct Answer: A
Solution :
\[\operatorname{Normality} = Molarity \times Valence\,\,factor\] \[\therefore \,\,\,\,\,\,Molarity\,\,=\,\,\frac{Normality}{Valence\,\,factor}\] Valence factor for oxalic acid \[=\,\,\,\frac{mol.\,wt.\,\,of\,\,oxalic\,\,acid}{Eq.\,wt.\,of\,oxalic\,acid}\] \[=\,\,\,\frac{mol.\,wt.\,\,of\,\,oxalic\,\,acid}{mol.\,wt.\,of\,oxalic\,acid}\times 2\] \[\left( As basicity = 2 for oxalic acid \right)\] \[Molarity\,\,=\,\,\frac{0.02}{2}=0.01\] \[\operatorname{Number} of\,\,millimoles = 0.01 \times 100\] \[\operatorname{Number} of moles =0.001\] \[\therefore \] No. of oxalic acid molecules \[= .001 \times 6.023 \times 1{{0}^{23}}= 6.023 \times 1{{0}^{20}}\]
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