NEET Sample Paper NEET Sample Test Paper-71

  • question_answer
    If a second-order reaction involving a single reactant is \[25%\] complete in 20 minutes, then what is its half-life if initial concentration of the reactant is being made double at the same temperature.

    A) 50 min             

    B) 30 min

    C) 60 min             

    D) 15 min

    Correct Answer: B

    Solution :

    \[\frac{1}{C}-\frac{1}{C{}^\circ }=kt\] (for second-order reaction) \[\frac{1}{\frac{3}{4}{{C}_{0}}}-\frac{1}{{{C}_{0}}}=k\times 20\] \[\frac{1}{\frac{1}{2}(2{{C}_{0}})}-\frac{1}{2{{C}_{0}}}=k\times {{t}_{1/2}}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\frac{\frac{1}{3{{C}_{0}}}}{\frac{1}{2{{C}_{0}}}}-\frac{20}{{{t}_{1/2}}}=\frac{2}{3}\times \frac{20}{{{t}_{1/2}}}\,\,=\,\,30\,\,\min utes\]


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