A) 438. 5 pm
B) 219.25 pm
C) 536.94 pm
D) 265.5 pm
Correct Answer: B
Solution :
For fcc lattice \[4r=\sqrt{2}where\,\,a= 620\,\,pm\] \[r=\frac{1}{2\sqrt{2}}\times a\] \[\frac{1}{2\sqrt{2}}\,\,\times 620 pm\, =\, 219.20 pm\]
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