A) Remain the same
B) Redoubled
C) Be quadrupled
D) Be halved
Correct Answer: C
Solution :
\[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\,\,\,\,\,\,\therefore \,\,\,\,\,H\propto {{u}^{2}}\]. If initial velocity be doubled, then maximum height reached by the projectile will be quadrupled.You need to login to perform this action.
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