A) 0.036
B) 0.36
C) 3.6
D) 36
Correct Answer: C
Solution :
\[{{n}_{2}}={{n}_{1}}\,{{\left( \frac{{{M}_{1}}}{{{M}_{2}}} \right)}^{1}}\,{{\left( \frac{{{L}_{1}}}{{{L}_{2}}} \right)}^{1}}\,{{\left( \frac{T}{{{T}_{2}}} \right)}^{-2}}\] \[=\,\,\,100{{\left( \frac{gm}{kg} \right)}^{1}}\,{{\left( \frac{cm}{m} \right)}^{1}}\,{{\left( \frac{\sec }{\min } \right)}^{-2}}\] \[=\,\,\,\,100{{\left( \frac{gm}{{{10}^{3}}\,gm} \right)}^{1}}\,{{\left( \frac{cm}{{{10}^{2}}\,cm} \right)}^{1}}\,{{\left( \frac{\sec }{60\,\sec } \right)}^{-\,2}}\] \[{{n}^{2}}=\frac{3600}{{{10}^{3}}}=3.6\]You need to login to perform this action.
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