A) 1 V
B) 3 V
C) 5 V
D) 4.2 V
Correct Answer: A
Solution :
To switch on the transistor, the emitter-base junction of a transistor is forward biased while collector-base junction is reverse biased. The cut-off voltage for silicon is \[\tilde{\ }1\text{ }V\], so to switch on a silicon transistor a potential difference of 1 V approximately is required between the base and emitter.
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