A) no current flows
B) the depletion region is increased
C) the depletion region is reduced
D) the height of the potential barrier is reduced
Correct Answer: B
Solution :
In reverse biasing, the applied voltage on the n-side is positive and is negative on the p-side. The applied bias V and the barrier potential Fg are the same direction making the effective junction potential\[V+{{V}_{B}}\]. As a result, the junction width will increase. The higher junction potential would restrict the flow of majority carriers to a much greater extent. However, such a field will favour the flow of minority carriers. So, reverse bias current will be due to the minority carriers only.
You need to login to perform this action.
You will be redirected in
3 sec
