A) \[BaS{{O}_{4}}\]
B) \[C{{a}_{3}}{{(P{{O}_{4}})}_{2}}\]
C) \[H{{g}_{2}}C{{l}_{2}}\]
D) \[A{{g}_{3}}P{{O}_{4}}\]
Correct Answer: C
Solution :
\[H{{g}_{2}}C{{l}_{2}}\underset{S}{\mathop{Hg_{2}^{2+}}}\,+\underset{2S}{\mathop{2C{{l}^{-}}}}\,\] \[{{K}_{SP}}=\left[ Hg_{2}^{2-} \right]\,{{\left[ C{{l}^{-}} \right]}^{2}}=(S)\,{{(2S)}^{2}}\] \[{{K}_{SP}}=4{{S}^{3}}\] \[S={{\left( \frac{{{K}_{SP}}}{4} \right)}^{{\scriptstyle{}^{1}/{}_{3}}}}\]
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