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NEET Sample Paper NEET Sample Test Paper-6

  • question_answer
    A 100W Bulb \[{{B}_{1}}\] and two \[60W\] bulbs \[{{B}_{2}}\] and \[{{B}_{3}}\] are connected to a \[250V\] source, as shown in the figure. Now \[{{W}_{1}},{{W}_{2}}\] and \[{{W}_{3}}\] are the output powers of the bulbs \[{{B}_{1}},\,{{B}_{2}}\] and \[{{B}_{3}}\] respectively, then,

    A)  \[{{W}_{1}}>{{W}_{2}}={{W}_{3}}\]

    B)  \[{{W}_{1}}>{{W}_{2}}>{{W}_{3}}\]

    C)  \[{{W}_{1}}<{{W}_{2}}={{W}_{3}}\]   

    D)  \[{{W}_{1}}<{{W}_{2}}<{{W}_{3}}\]

    Correct Answer: D

    Solution :

    Resistances of bulbs \[{{B}_{2}}\] and \[{{B}_{3}}\] are equal but that of \[{{B}_{1}}\] is smaller than their resistances, hence resistances of path of bulb \[{{B}_{3}}\] is less that of the series combination of bulbs \[{{B}_{2}}\] and \[{{B}_{1}}\], therefore power consumed by Bo will be maximum possible. Since, \[{{B}_{1}}\] and \[{{B}_{2}}\] are in series, therefore current through them will be the same. Since resistance of \[{{B}_{2}}\] is greater, therefore \[{{W}_{2}}>{{W}_{1}}\]


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