A) F
B) F/2
C) 2F
D) 4F
Correct Answer: C
Solution :
As, the kinetic energy \[K=\frac{1}{2}m{{\omega }^{2}}({{A}^{2}}-{{X}^{2}})\] \[=\frac{1}{2}m{{\omega }^{2}}[{{A}^{2}}-{{A}^{2}}{{\sin }^{2}}\omega t]\] \[=\frac{1}{2}m{{\omega }^{2}}{{A}^{2}}{{\cos }^{2}}\omega t\] \[=\frac{1}{2}m{{\omega }^{2}}{{A}^{2}}\left( \frac{1+{{\cos }^{2}}\omega t}{2} \right)\] Here, we see the frequency is doubled.
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