NEET Sample Paper NEET Sample Test Paper-68

  • question_answer
    The correct set of four quantum numbers for the valence electron of rubidium atom \[\left( Z = 37 \right)\] is

    A) \[5,\,0,\,0,+\frac{1}{2}~\]                     

    B) \[5,\,\,1,\,\,0,\,\,+\frac{1}{2}\]

    C) \[5,\,\,1,\,\,1,\,\,+\frac{1}{2}\]               

    D) \[6,\,\,0,\,\,0,\,\,+\frac{1}{2}\]

    Correct Answer: A

    Solution :

    The electronic configuration of \[_{37}Rb\] is: \[1{{s}^{2}},\,2{{s}^{2}}2{{p}^{6}},\,3{{s}^{2}}3{{p}^{6}}3{{d}^{10}},\,4{{s}^{2}}4{{p}^{6}},\,5{{s}^{1}}\,\]\[\operatorname{n}=5,\,\,l=0,\,\,m=0,\,\,s=+\frac{1}{2}\,\,or\,\,-\frac{1}{2}\]


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