A) \[{{H}_{2}}S{{O}_{4}}\,with\,\,NaOH\]
B) In atmosphere, \[{{O}_{3}}\,\,from\,\,{{O}_{2}}\] by lightning
C) Evaporation of \[{{H}_{2}}O\]
D) Nitrogen oxides form nitrogen and oxygen by lightning
Correct Answer: D
Solution :
\[2\overset{0}{\mathop{{{N}_{2}}}}\,+\overset{0}{\mathop{{{O}_{2}}}}\,\,\,\to \,\,\overset{+2\,-2}{\mathop{2N\,O}}\,\] Here oxidation number of N increases from 0 in \[\,{{N}_{2}}\] to +2 in NO, and that of O decreased from 0 in \[{{O}_{2}}\] to -2 in NO, therefore, it is a redox reaction.
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