NEET Sample Paper NEET Sample Test Paper-68

  • question_answer
    The volume of oxygen liberated from 0.68 g of \[{{H}_{2}}{{O}_{2}}\] is

    A) 112 ml             

    B) 56 ml

    C) 224 ml             

    D) 336 ml

    Correct Answer: C

    Solution :

    We know that \[2{{H}_{2}}{{O}_{2}}\,\,\to \,\,2{{H}_{2}}O+{{O}_{2}}\] \[\because \,\,\,2\,\,\times \,\,34\text{ }g\,\,\,\,\,\,\,\,~22400\text{ }ml\] \[\because  \,2\,\,\times \,\,34 g =\, 68 g of {{H}_{2}}{{O}_{2}} liberates\] \[22400\text{ }ml\text{ }{{O}_{2}}\text{ }at\text{ }STP\] \[=\,\,\frac{0.68\times 22400}{68}\,\,=\,\,224\,ml\]


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