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NEET Sample Paper NEET Sample Test Paper-68

  • question_answer
    The sulphate of a metal M contains \[9.87\,%\] of M. This sulphate is isomorphous with\[ZnS{{O}_{4}}\,\cdot \,7{{H}_{2}}O\]. The atomic weight of M is

    A) 40.3                 

    B) 36.3

    C) 24.3                             

    D) 11.3

    Correct Answer: C

    Solution :

    As the given sulphate is isomorphous with \[ZnS{{O}_{4}}\cdot 7{{H}_{2}}O\] its formula would be \[MS{{O}_{4}}\cdot 7{{H}_{2}}O\] m is the atomic weight of M, molecular weight of \[\operatorname{MS}{{O}_{4}}\cdot 7{{H}_{2}}O=m+32+64+126 =m+222\] Hence \[% of\,\,M=\frac{m}{m+22}\times  100 =9.87 \left( given \right)\] \[100 m= 9.87m\,\,+\,\,222\,\,\times \,\,9.87\] or \[90.13\,m \,=\,\,222\,\,\times \,\,9.87\] \[or\,\,m=\frac{222\times 9.87}{90.13}\,\,=\,\,24.3\,\]


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