A) 25 N
B) 100 N
C) 50 N
D) \[\frac{50}{\sqrt{3}\,}\,N\]
Correct Answer: C
Solution :
Let P force is acting at an angle \[30{}^\circ \] with the horizontal. For the condition of motion \[\operatorname{F} \,=\, \mu \,R\] \[\operatorname{P} cos\,\,30{}^\circ \,=\,\,m (mg - P\,sin 30{}^\circ )\] \[\Rightarrow \,\,\,\,P\frac{\sqrt{3}}{2}=\frac{1}{\sqrt{3}}\left( 100-P\frac{1}{2} \right)\] \[\Rightarrow \,\,\frac{3P}{2}=\,\,\left( 100-\frac{P}{2} \right)\] \[\Rightarrow \,\,\,\,2P=100\,\, \therefore \,\, P=50\,\,N\]
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