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NEET Sample Paper NEET Sample Test Paper-68

  • question_answer
    The motion of a particle along a straight line is   described by equation: \[\operatorname{x}= 8 +12t - {{t}^{3}}\] where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is                

    A) \[12\,\,m{{s}^{-2}}\]               

    B) \[24\,\,m{{s}^{-2}}\]

    C) zero                              

    D) \[6\,\,m{{s}^{-2}}\]

    Correct Answer: A

    Solution :

    \[v=\frac{dx}{dt}=\,\,12-3{{t}^{2}}=0\]                                  ?. (i) If velocity is zero, \[12-3{{t}^{2}}=0\] which gives \[t=0\] sec For acceleration again differential equation (i) At time \[\operatorname{t}=2 sec,\,\,a=-6 \times  2= -12 m/{{s}^{2}}\] Hence retardation \[=\,\,12\,m/{{s}^{2}}\]


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