A) 0.4
B) 40
C) 400
D) 0.04
Correct Answer: B
Solution :
Mass, \[M=\rho V\,\,\,\,\Rightarrow \,\,\,\,\,\,\rho =\frac{M}{V}=\frac{M}{{{L}^{3}}}\] We are given \[\rho = 4 g/c{{m}^{3}}\] If unit of mass is 100 g and unit of distance is 10 cm. So, density \[=\,\,\frac{4\left( \frac{100\,g}{100} \right)}{{{\left( \frac{10}{10}\,cm \right)}^{3}}}\,\,=\,\,\frac{\left( \frac{4}{100} \right)}{{{\left( \frac{1}{10} \right)}^{3}}}\,\,\cdot \,\,\frac{(100\,g)}{{{(10\,\,cm)}^{3}}}\,\] \[=\,\,40\,g\,c{{m}^{-3}}\] \[Aliter\,:\,\,{{u}_{2}}={{u}_{1}}\left( \frac{{{M}_{1}}}{{{M}_{2}}} \right){{\left( \frac{{{L}_{1}}}{{{L}_{2}}} \right)}^{-\,3}}\,\,=\,\,4\left( \frac{1}{100} \right){{\left( \frac{\,1}{10} \right)}^{-\,3}}\]
You need to login to perform this action.
You will be redirected in
3 sec
