A) N-type and its resistivity is 0.34 ohm-metre
B) P-type and its resistivity is 0.034 ohm-metre
C) N-type and its resistivity is 0.034 ohm-metre
D) P-type and its resistivity is 3.40 ohm-metre
Correct Answer: A
Solution :
\[{{n}_{e}}\,=\,\,8\times 1{{0}^{18}}/{{m}^{3}},\,\,{{n}_{h}}=5\times 1{{0}^{18}}/{{m}^{3}},\] \[{{\mu }_{e}}=2.3\frac{{{m}^{2}}}{volt-\sec },\,\,\,{{\mu }_{h}}=0.01\frac{{{m}^{2}}}{volt-\sec }\] \[\because \,\,\,{{n}_{e}}>{{n}_{h}}\,\,\] so semiconductor is N-type Also conductivity \[\sigma =\frac{1}{\operatorname{Re}sistivity\,(\rho )}\,\,=\,\,e({{n}_{e}}{{\mu }_{e}}+{{n}_{h}}{{\mu }_{h}})\] \[\Rightarrow \,\,\frac{1}{\rho }=1.6\times {{10}^{-19}}\,\left[ \begin{matrix} 8\times {{10}^{18}}\times 2.3 \\ \,\,\,\,\,+5\times {{10}^{18}}\times 0.01 \\ \end{matrix} \right]\] \[\Rightarrow \,\,\, \rho = 0.34 \Omega -m.\]
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