A) \[1\times {{10}^{2}}\,c{{m}^{3}}\]
B) \[2\times {{10}^{2}}\,c{{m}^{3}}\]
C) \[1.763\times {{10}^{2}}\,c{{m}^{3}}\]
D) none of these
Correct Answer: B
Solution :
\[Volume\,\,V= l\,\,\times b\,\,\times t\] \[=\,\,\,12\times 6\times 2.45=176.4\,\,c{{m}^{3}}\] \[V=1.764\times {{10}^{2}}\,{{m}^{3}}\] Since the minimum number of significant figure is one in breadth, hence volume will also contain only one significant figure. Hence, \[\operatorname{V} = 2\,\,\times 1{{0}^{2}}c{{m}^{3}}\].
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