A) \[\frac{\pi }{10}\,V\]
B) \[\frac{2\pi }{10}\,V\]
C) \[10\,\pi \,mV\]
D) \[20\,\pi \,mV\]
Correct Answer: C
Solution :
The induced emf between centre and rim of the rotating disc is \[E=\frac{1}{2}\,B\omega {{R}^{2}}\] \[=\,\,\frac{1}{2}\times 0.1\times 2\pi \times 10\times {{(0.1)}^{2}}\] \[=\,\,10\pi \,\,\times \,\,1{{0}^{-}}^{3}\,volt\]
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