A) \[P=W\,tan\,\theta \]
B) \[\vec{T}+\vec{P}+\vec{W}=0\]
C) \[{{T}^{2}}={{P}^{2}}+{{W}^{2}}\]
D) \[T=P+W\]
Correct Answer: D
Solution :
As the metal sphere is I n equilibrium under the effect of three forces therefore \[\vec{T} + \vec{P} + \vec{W} =0~~~~~~~~~~\] From the figure \[T\,\,cos\,\,\theta \,\,=\,\,W\] ?. (i) \[T\,\,\sin \,\,\theta \,\,=\,\,P\] .... (ii) From equations (i) and (ii), we get \[P=W\,\,\tan \,\theta \] and \[{{T}^{2}}= {{P}^{2}}+ {{W}^{2}}\]You need to login to perform this action.
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