A) 10 R
B) 20 R
C) 30 R
D) 40 R
Correct Answer: B
Solution :
\[W=\int{PdV}\,\,=\,\,\int{\frac{RT}{V}dV}\] Since \[\operatorname{V}=k{{T}^{2/3}}\,\,\Rightarrow \,\,dV=\,\,\frac{2}{3}\,K{{T}^{-1/3}}\,dT\] Eliminating K, we find \[\frac{dV}{V}=\frac{2}{3}\,\frac{dT}{T}\] Hence \[W=\int_{{{T}_{1}}}^{{{T}_{2}}}{\frac{2}{3}}\,\,\frac{RT}{T}\,dT\] \[=\,\,\,\frac{2}{3}R({{T}_{2}}-{{T}_{1}})\,\,=\,\,\frac{2}{3}\,R(30)\,\,=\,\,20R\]You need to login to perform this action.
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