A) 1150 N
B) 1250 N
C) 1300 N
D) 1420 N
Correct Answer: B
Solution :
Friction between block A and block B and between block B and surface will oppose the P \[\therefore \,\,\,\,P={{F}_{AB}}+{{F}_{BS}}\] \[=\,\,{{\mu }_{AB}}{{m}_{A}}g\,\,+\,\,{{\mu }_{BS}}\,({{m}_{A}}+{{m}_{B}})\,g\] \[=\,\,0.25\times 100\times 10+\frac{1}{3}\,(100+200)\times 10\] \[=\,\,1250\,N\]You need to login to perform this action.
You will be redirected in
3 sec