A) T
B) 9T
C) 27T
D) T/9
Correct Answer: B
Solution :
\[V{{P}^{3}}= constant\,\,=\, k\,\,\Rightarrow \,\,P=\,\,\frac{k}{{{V}^{1/3}}}\] Also \[PV=\mu RT\,\,\Rightarrow \,\,\frac{k}{{{V}^{1/3}}}\,.V\,\,=\,\,\mu RT\] \[\Rightarrow \,\,\,\,{{V}^{2/3}}\,=\,\,\frac{\mu RT}{k}\] Hence \[\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right){{\,}^{2/3}}\,=\,\,\frac{{{T}_{1}}}{{{T}_{2}}}\,\,\,\Rightarrow \,\,{{\left( \frac{V}{27V} \right)}^{2/3}}\,\,=\,\,\,\frac{T}{{{T}_{2}}}\] \[\Rightarrow \,\,\,\,{{T}_{2}}\,=\,\,9\,T\]You need to login to perform this action.
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