A) n-propyl bromide
B) ethyl bromide and n-butyl bromide
C) ethyl chloride and n -butyl chloride
D) methyl bromide and n -pentyl chloride
Correct Answer: A
Solution :
According to Wurtz reaction. \[2C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\,\,+\,\,2Na\,\,\xrightarrow{ether}\] \[C{{H}_{3}}{{\left( C{{H}_{2}} \right)}_{4}}C{{H}_{3}}+2NaBr\]
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