A) \[60\times {{10}^{-}}^{3}\]
B) \[20\times {{10}^{-}}^{3}\]
C) 1.200
D) \[10.3\times {{10}^{-}}^{3}\]
Correct Answer: A
Solution :
\[{{N}_{2}}(g)\,\,+\,\,3{{H}_{2}}(g)\,\,\to \,\,2N{{H}_{3}}(g)\] \[\frac{-d({{N}_{2}})}{dt}\,\,=\,\,\frac{1}{3}\,\frac{d({{H}_{2}})}{dt}\,\,=\,\,\,\frac{1}{2}\,\frac{d(N{{H}_{3}})}{dt}\] \[=\,\,\frac{3}{2}\times \,40\,\,\times \,\,{{10}^{-\,3}}\,\,=\,\,60\,\times \,{{10}^{-3}}\]You need to login to perform this action.
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