A) \[_{17}C{{l}^{35}}\]
B) \[_{19}C{{l}^{27}}\]
C) \[_{17}C{{l}^{37}}\]
D) \[_{19}C{{l}^{39}}\]
Correct Answer: C
Solution :
\[_{17}C{{l}^{37}}\,+{{\,}_{1}}{{H}^{2}}\,\,\to \,{{\,}_{18}}A{{r}^{38}}\,+{{\,}_{0}}{{n}^{1}}\]You need to login to perform this action.
You will be redirected in
3 sec