NEET Sample Paper NEET Sample Test Paper-64

  • question_answer
    The electronic configuration of four elements L, P, Q and R are given in brackets
    \[L\left( 1{{s}^{2}},\text{ }2{{s}^{2}}\,2{{p}^{4}} \right);\text{ }Q\left( 1{{s}^{2}},\,\,2{{s}^{2}}\,\,2{{p}^{6}},\text{ }3{{s}^{2}}\,3{{p}^{5}} \right)\]
    \[P\left( 1{{s}^{2}},\text{ }2{{s}^{2}}\,\,2{{p}^{6}},\text{ }3{{s}^{1}} \right);\,\,R\left( 1{{s}^{2}},2{{s}^{2}}\,\,2{{p}^{6}},\text{ }3{{s}^{2}} \right)\]
    The formulae of ionic compounds that can be formed between these elements are

    A) \[{{L}_{2}}P,\,\,RL,\,\,PQ\,\,and\,\,{{R}_{2}}Q\]

    B) LP, RL, PQ and RQ

    C) \[{{P}_{2}}L,\,\,RL,\,\,PQ\,\,and\,\,R{{Q}_{2}}\]

    D) \[LP,\,\,{{R}_{2}}L,\,\,{{P}_{2}}Q\,\,and\,\,RQ\]

    Correct Answer: C

    Solution :

    Valencies of L, Q, P and R is -2, -1, +1 and +2 respectively so they will form\[{{P}_{2}}L,\,\,RL,\,\,PQ\,\,\,and\,\,R{{Q}_{\text{2}}}\].


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