A) energy
B) force
C) energy per unit volume
D) force per unit volume
Correct Answer: C
Solution :
\[\Pr essure\,\,=\,\,\frac{Force}{Area}\,\,=\,\,\frac{\left[ ML{{T}^{-2}} \right]}{\left[ {{L}^{2}} \right]}\,\,=\,\,\left[ M{{L}^{-1}}{{T}^{-\,2}} \right]\] \[Energy per unit volume\,\,=\,\,\frac{\left[ M{{L}^{2}}{{T}^{-2}} \right]}{\left[ {{L}^{3}} \right]}\] \[=\text{ }\left[ M{{L}^{-}}^{1}\,{{T}^{-2}} \right]\]
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