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NEET Sample Paper NEET Sample Test Paper-64

  • question_answer
    200 Me V of energy may be obtained per fission\[{{U}^{235}}\]. A reactor is generating 1000 kW of power. The rate of nuclear fission in the reactor is

    A) 1000                

    B) \[2\,\,\times {{10}^{8}}\]

    C) \[3.125\,\,\times {{10}^{16}}\]             

    D) 931

    Correct Answer: C

    Solution :

    \[Powers\,\,\Rightarrow \,\,{{\left( \frac{1}{2} \right)}^{4}}\,=\,\,{{\left( \frac{1}{2} \right)}^{t/48}}\,\,\,\,\Rightarrow \,\,\,\,t=192\,\,h\] \[\,Rate\text{ }of\text{ }nuclear\text{ }fission\,\,=\,\,\frac{{{10}^{6}}}{200\times 1.6\times {{10}^{-13}}}\] \[=3.125\,\,\times \,\,{{10}^{16}}.\]


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