A) \[\left( g+a \right)\,\sin \,\theta ~\]
B) \[\left( g-a \right)\]
C) \[g\,\,sin\,\,\theta \]
D) \[\left( g-a \right)\text{ }sin\,\theta \]
Correct Answer: A
Solution :
Acceleration of block in a stationary lit\[=\,\,g\,\,\sin \,\theta \]. If lift is descending with acceleration then it will be \[\left( g - a \right)\,\,sin\,\theta \], but in the problem acceleration =-a (retardation)You need to login to perform this action.
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