A) 6.55 T
B) 5.66 T
C) 0.655 T
D) 0.566 T
Correct Answer: D
Solution :
\[q=-\frac{N}{R}\,({{B}_{2}}-{{B}_{1}})\,A\,\cos \,\theta \] \[32\times {{10}^{-}}^{6}\] \[=-\frac{100}{(160+40)}\,\,(0-B)\times \pi \times {{(6\times {{10}^{-3}})}^{2}}\,\times \,\,cos\,0{}^\circ \] \[\Rightarrow \,\,B\,\,=\,\,0.565\text{ }T\]You need to login to perform this action.
You will be redirected in
3 sec