NEET Sample Paper NEET Sample Test Paper-64

  • question_answer
    Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are 0.8 and 0.6 and surface tensions are 60 and 50 dyne/cm respectively Ratio of heights of liquids in the two tubes \[{{h}_{1}}/{{h}_{2}}\] is

    A) \[\frac{10}{9}\]                         

    B) \[\frac{3}{10}\]

    C) \[\frac{10}{3}\]                         

    D) \[\frac{9}{10}\]

    Correct Answer: D

    Solution :

    Ascent formula \[h=\frac{2T\,\cos \,\theta }{rdg}\] \[\Rightarrow \,\,\,\frac{{{h}_{1}}}{{{h}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\times \frac{{{d}_{2}}}{{{d}_{1}}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(r,\,\theta \,and\,\,g\,\,are\,\,cons\tan ts\,)\]\[\Rightarrow \,\,\,\frac{{{h}_{1}}}{{{h}_{2}}}=\frac{60}{50}\times \frac{0.6}{0.8}=\,\,\frac{9}{10}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner