A) 19.6 N
B) 1.96 N
C) 9.8 N
D) zero
Correct Answer: B
Solution :
\[T=mg\,+\,\frac{m{{v}^{2}}}{l}\] \[=\,\,mg\,+\,\frac{m}{l}\,\left[ 2\,gl\,(1-cos\,\theta ) \right]\] \[=mg+2mg(1-cos\text{ }60{}^\circ )\] \[=\,\,2\,\,mg\,=\,\,2\times 0.1\times 9.8\,\,=\,\,1.96\,\,N\]You need to login to perform this action.
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