A) 4 V
B) 8 V
C) (e) 12 V
D) 16 V
Correct Answer: B
Solution :
Switch \[{{S}_{2}}\] is open so capacitor is not in circuit Current through \[3\,\Omega \] resistor \[=\,\,\,\frac{24}{3+3}\,\,4\,A\] Let potential of point ?O? shown in the figure is \[{{V}_{0}}\] then using Ohm?s law \[{{V}_{a}}-{{V}_{a}}=3\times 4=12\,\,V\] ?. (i) Now current through \[5\,\Omega \] resistor \[=\,\,\frac{24}{5+1}\,\,=\,\,4\,A\] So \[{{V}_{a}}-{{V}_{b}}=4\times 1\,\,=\,\,4\,V\] ?. (ii) From equations (i) and (ii) \[{{V}_{b}}-{{V}_{a}}\,\,=\,\,12-4\,\,=\,\,8\,\,V\]You need to login to perform this action.
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