A) \[y = A\,\,sin\left( \omega t + kx \right)\]
B) \[y = -0.8\,A\,\,sin\left( \omega t + kx \right)\]
C) \[y = 0.8\,A\,\,sin\left( \omega t + kx \right)\]
D) \[y = A\,\,sin\left( \omega t +0.8 kx \right)\]
Correct Answer: B
Solution :
On getting reflected from a rigid boundary Ac wave suffers. Hence if \[{{\text{y}}_{incident}}=A\,\,\sin \,(\omega t-kx)\] \[{{\text{y}}_{reflected}}=(0.8\,A)\,\,\sin \,\{\omega t-k(-x)+\pi \}\] \[=\,\,-0.8\,A\,\sin \,(\omega t\,+\,\,kx)\,\,\] an additional phase change of \[\pi \]
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