question_answer

Two wires of same metal have the same length but their cross sections are in the ratio 3 : 1. They are joined in series. The resistance of the thicker wire is\[10\Omega \]. The total resistance of the combination will be:

A) \[\frac{5}{2}\Omega \]                          

B) \[40\Omega \]

C) \[\frac{40}{3}\Omega \]             

D) \[100\Omega \]