A) \[\frac{v}{c}\]
B) \[\frac{v}{2c}\]
C) \[\frac{v}{3c}\]
D) \[\frac{v}{4c}\]
Correct Answer: B
Solution :
[b] de-broglie wavelength \[\lambda =\frac{h}{\sqrt{2m{{E}_{e}}}}\,......(1)\] \[\lambda =\frac{hc}{{{E}_{p}}}.....(2)\] From (1) & (2) \[2m\,{{E}_{e}}=\frac{{{E}_{p}}}{{{C}^{2}}}\therefore {{E}_{e}}=\frac{1}{2}m{{v}^{2}}\Rightarrow m=\frac{2{{E}_{e}}}{{{v}^{2}}}\] \[2\left[ \frac{2{{E}_{e}}}{{{v}^{2}}} \right]{{E}_{e}}=\frac{E_{p}^{2}}{{{c}^{2}}}\] We get \[\frac{{{E}_{e}}}{{{E}_{p}}}\frac{v}{2c}\]
You need to login to perform this action.
You will be redirected in
3 sec
