A) \[C{{H}_{3}}C{{H}_{2}}COCl\]
B) \[C{{H}_{3}}C{{H}_{2}}CHO\]
C) \[C{{H}_{2}}=CHCOOH\]
D) \[CIC{{H}_{2}}C{{H}_{2}}COOH\]
Correct Answer: C
Solution :
[c] \[C{{H}_{3}}=CHCOOH\] \[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow{C{{l}_{2}}/red\,P}\] \[C{{H}_{3}}-\underset{(A)}{\mathop{CHCl-COOH}}\,\xrightarrow[-HCl]{Alc,KOH}\] \[C{{H}_{2}}=\underset{(B)}{\mathop{CH-COOH}}\,\]
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