A) \[{{K}^{+}}>N{{a}^{+}}>R{{b}^{+}}>C{{s}^{+}}\]
B) \[C{{s}^{+}}>R{{b}^{+}}>{{K}^{+}}>N{{a}^{+}}\]
C) \[R{{b}^{+}}>{{K}^{+}}>C{{s}^{+}}>N{{a}^{+}}\]
D) \[N{{a}^{+}}>{{K}^{+}}>R{{b}^{+}}>C{{s}^{+}}\]
Correct Answer: B
Solution :
[b] \[C{{s}^{+}}>R{{b}^{+}}>{{K}^{+}}>N{{a}^{+}}\] Smaller the size of an ion, more strongly, it is hydrated and less is the ionic mobility. The sizes of unhydrated ions increase in the order: \[N{{a}^{+}}<{{K}^{+}}<R{{b}^{+}}<C{{S}^{+}}\] The sizes of hydrated ions will be in the order: \[C{{s}^{+}}>R{{b}^{+}}>{{K}^{+}}>N{{a}^{+}}\] Hence, their ionic mobilities will be in the order: \[C{{s}^{+}}>R{{b}^{+}}>{{K}^{+}}>N{{a}^{+}}\]
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