A) \[{{(C{{H}_{3}})}_{2}}\,\overset{\bullet }{\mathop{C}}\,H<{{(C{{H}_{3}})}_{3}}\,\overset{\bullet }{\mathop{C}}\,<{{({{C}_{6}}{{H}_{5}})}_{2}}\overset{\bullet }{\mathop{C}}\,H<{{({{C}_{6}}{{H}_{5}})}_{3}}\overset{\bullet }{\mathop{C}}\,\]
B) \[{{({{C}_{6}}{{H}_{5}})}_{3}}\,\overset{\bullet }{\mathop{C}}\,<{{({{C}_{6}}{{H}_{5}})}_{2}}\,\overset{\bullet }{\mathop{C}}\,H<{{(C{{H}_{3}})}_{3}}\overset{\bullet }{\mathop{C}}\,<{{(C{{H}_{3}})}_{2}}\overset{\bullet }{\mathop{C}}\,H\]
C) \[{{({{C}_{6}}{{H}_{5}})}_{2}}\,\overset{\bullet }{\mathop{CH}}\,<{{({{C}_{6}}{{H}_{5}})}_{3}}\,\overset{\bullet }{\mathop{C}}\,<{{(C{{H}_{3}})}_{3}}\overset{\bullet }{\mathop{C}}\,<{{(C{{H}_{3}})}_{2}}\overset{\bullet }{\mathop{C}}\,H\]
D) \[{{(C{{H}_{3}})}_{2}}\,\overset{\bullet }{\mathop{CH}}\,<{{(C{{H}_{3}})}_{3}}\,\overset{\bullet }{\mathop{C}}\,<{{({{C}_{6}}{{H}_{5}})}_{3}}\overset{\bullet }{\mathop{C}}\,<{{({{C}_{6}}{{H}_{5}})}_{2}}\overset{\bullet }{\mathop{C}}\,H\]
Correct Answer: A
Solution :
[a] More the number of phenyl groups, greater is the stabilization due to resonance, therefore \[{{({{C}_{6}}{{H}_{5}})}_{3}}CH\]is more stable than \[{{({{C}_{6}}{{H}_{5}})}_{2}}CH\]further, more the number of methyl groups, larger is the number of hyper conjugation structures and hence more stable is the radical, i.e. \[{{(C{{H}_{3}})}_{3}}C\] is more stable than \[{{(C{{H}_{3}})}_{2}}CH\]. Thus [a] is correct, represents increasing order stability of the radicals.
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