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NEET Sample Paper NEET Sample Test Paper-60

  • question_answer
    1 mole of \[{{N}_{2}}\] and 2 moles of \[{{H}_{2}}\] are allowed to react in \[d{{m}^{3}}\]vessel. At equilibrium, 0.8 mole of \[N{{H}_{3}}\]is formed. The concentration of \[{{H}_{2}}\] in the vessel is:

    A) 0.6 mole           

    B) 0.8 mole

    C) 0.2 mole           

    D) 0.4 mole

    Correct Answer: B

    Solution :

    [b] 0.8 mole \[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}}\] formation of 0.8 mole of \[N{{H}_{3}}\] means that \[\frac{3}{2}\times 0.8\] mole of \[{{H}_{2}}\] have reacted. Hence, concentration of \[{{H}_{2}}=2-\frac{3}{2}\times 0.8\]                         \[=2-3\times 0.4\]                         \[=2-1.2=0.8\,mole\]


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