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NEET Sample Paper NEET Sample Test Paper-60

  • question_answer
    A body is projected horizontally from the top of a tower with a speed of 20m/s. After 4 sec the displacement of the body is:

    A) \[40m\]             

    B) \[80m\]

    C) \[80\sqrt{2m}\]              

    D) \[\frac{80}{\sqrt{2}}m\]

    Correct Answer: C

    Solution :

    [c] Range \[=20\times 4=80m\] Y (vertical distance) \[=\frac{1}{2}\times 10\times {{(4)}^{2}}=80m\]Displacement \[=\sqrt{{{R}^{2}}+{{Y}^{2}}}=\sqrt{{{(80)}^{2}}+{{(80)}^{2}}}\Rightarrow 80\sqrt{2m}\]


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