question_answer

A junction diode has a resistance of 25ft when forward biased and 2500ft when reverse biased. The current in the diode for the arrangement shown will be:

A) \[\frac{1}{15}A\]                      

B) \[\frac{1}{7}A\]

C) \[\frac{1}{25}A\]                      

D) \[\frac{1}{480}A\]

Correct Answer: B

Solution :

[b]  Forward biased \[5-0=(10+25)I\] \[I=\frac{5}{35}\] \[I=\frac{1}{7}A\]