A) \[4.\,35\times {{10}^{-2}}J\]
B) \[4.35\times {{10}^{-3}}J\]
C) \[4.35\times {{10}^{-6}}J\]
D) \[4.35\times {{10}^{-8}}J\]
Correct Answer: A
Solution :
[a] Radius of drop, R = 1cm = 10m \[r={{10}^{-4}}m\] Volume constant \[\Rightarrow \,\frac{4}{3}\pi {{r}^{3}}=n\times \frac{4}{3}\pi {{r}^{3}}\] \[\Rightarrow \,R={{n}^{{}^{1}/{}_{3}}}\,r\] \[\Delta \,A=n4\pi {{r}^{2}}-4\pi {{R}^{2}}\] \[\Delta A=4\times 9.9\pi \times {{10}^{-3}}\] Work done \[=T\Delta A\] \[=(35\times {{10}^{-2}})\times 4\times 99\times 3.14\times {{10}^{-3}}=4.35\times {{10}^{-2}}J\]
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