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NEET Sample Paper NEET Sample Test Paper-60

  • question_answer
    A proton carrying 1MeV kinetic energy is moving in a circular path of radius R in uniform magnetic field. What should be the energy of an\[\alpha \]particle to describe a circle a circle of same radius in the same field?

    A) 2MeV                           

    B) 1 MeV

    C) 0.5MeV                        

    D) 4 MeV

    Correct Answer: B

    Solution :

    [b] Radius of the circular path of a charged particle in uniform magnet field \[R=\frac{mv}{qB}=\frac{m}{Bq}\sqrt{\frac{2k}{m}}=\sqrt{\frac{2mk}{Bq}}\] For proton mass = m charge = q For a-particle mass = 4m charge = 2q \[{{R}_{\alpha }}=\frac{\sqrt{2\,(4m)k}}{B\,(2q)}=\frac{\sqrt{2m{{k}_{\alpha }}}}{Bq}\]             \[\frac{{{R}_{p}}}{{{R}_{\alpha }}}=\sqrt{\frac{{{k}_{p}}}{{{k}_{\alpha }}}}\]             As RP=R (given) \[{{K}_{\alpha }}={{K}_{p}}=1MeV\]


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