A) \[C{{H}_{3}}\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}\]
B) \[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{2}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,H\]
C) \[C{{H}_{3}}-C{{H}_{2}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,H\]
D) \[C{{H}_{3}}-C{{H}_{2}}OH+C{{H}_{3}}OH\]
Correct Answer: B
Solution :
Two molecules of acetaldehyde gives aldol on Aldol condensation. \[\underset{acetaldehyde}{\mathop{2C{{H}_{3}}CHO}}\,\xrightarrow{O{{H}^{-}}}C{{H}_{3}}-\underset{Aldol}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,H-C{{H}_{2}}-CHO\]
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