A) \[RCOOH>{{H}_{2}}C{{O}_{3}}>{{C}_{6}}{{H}_{5}}OH>{{H}_{2}}O>ROH\]
B) \[RCOOH>ROH>{{H}_{2}}C{{O}_{3}}>{{C}_{6}}{{H}_{5}}OH>{{H}_{2}}O\]
C) \[ROH>RCOOH>{{H}_{2}}C{{O}_{3}}>{{C}_{6}}{{H}_{5}}OH>{{H}_{2}}O\]
D) \[RCOOH>{{C}_{6}}{{H}_{5}}OH>ROH>{{H}_{2}}C{{O}_{3}}>{{H}_{2}}O\]
Correct Answer: A
Solution :
The order of acidity of \[RCOOH,{{H}_{2}}C{{O}_{3}},{{C}_{6}}{{H}_{5}}OH,{{H}_{2}}O\]and \[ROH\] is as: \[RCOOH>{{H}_{2}}C{{O}_{3}}>{{C}_{6}}{{H}_{5}}OH>{{H}_{2}}O>ROH\]Increasing acid strength (increasing Ka)
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